Calculating the helicopter cut on Kong’s hand

Saw a conversation about this cut and decided to push my calculations,

Do note that I’m fairly new at actual calculations and could get things wrong

The helicopter Kong Grabbed was a CH-53 Sea Stallion

The tail Rotor has a diameter of 16 feet, or 4.88 Meters, and they rotate at 792 RPM

If we convert RPM to MPH, that would mean that these blades were moving at 905 mph.

If we were to use the weight of, say a BlackHawk, which has smaller blades but are made of the same alloy, you have 4352 lbs of force.

And the cuts left on Kong were visibly shallow. As it stopped bleeding a few hours after his fight with the Choppers. Only leaving Kong with Capillary bleeding, since it stopped bleeding a few hours after the fight, and Kong showed that he didn’t really do anything to stop the Bleeding.

In other words, 2 tons of force only left shallow cuts in Kong’s hand as a juvenile