AAMC FL 4 | C/P | Q13
After reviewing this question, I understand that we must know f = r/2 to solve this question. Nearsightedness = focal length too short = image focuses in front of the retina. We solve nearsightedness by increasing r (radius of curvature). Ok cool, but would the opposite apply to fix farsightedness? Using f = r/2, I would figure that we would decrease r so that our focal length decreases. But, it seems that Fig. 2A is going with a different approach unrelated to f = r/2. In this case, how would solve this question if AAMC worded this question instead as, " What is the effect produced by the PRK technique designed to correct farsightedness?". Any help would be greatly appreciated! I just want to make sure I understand this concept well :)
